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Yes - assuming that you can neglect air resistance, the horizontal velocity is constant. So horizontal velocity = horizontal distance traveled divided by elapsed time. The horizontal displacement of the projectile is called the range of the projectile and depends on the initial velocity of the object. If an object is projected at the same initial speed, but two complementary angles of projection, the range of the projectile will be the same.

If a projectile has a time of flight of 8 seconds and a horizontal velocity of 20 m/s, then the horizontal displacement is 160 meters (20 m/s • 8 s). If a projectile has a time of flight of 8 seconds and a horizontal velocity of 34 m/s, then the projectile has a horizontal displacement of 272 meters... Nov 17, 2013 · Projectile Motion: How to solve for initial vertical and Horizontal Velocity. May 15, 2018 · For a general velocity problem you can simply write an equation using "V" for velocity, such as V = a × t. However, to write a motion equation that treats horizontal and vertical velocity separately, you must distinguish the two by using Vx and Vy, for horizontal and vertical velocity, respectively. The free fall motion of any object in a horizontal path with constant velocity is Projectile Motion. Projectile Motion Formula (trajectory formula) is articulated as. Where, the velocity along the x-axis is V x , the initial velocity along the x-axis is V xo , the velocity along the y-axis is V y , the initial velocity along the y-axis is V yo .

Horizontal range of a projectile Say R is the horizontal range covered by a projectile is R when it touches the ground after passing the time T max Here we will use the horizontal component of the velocity only as the effective velocity to traverse this horizontal path. R = (V 0 cosθ).